Introduction
JEE Main 2025 cutoff is released by the National Testing Agency (NTA) that is needed to get qualified to appear for JEE Advanced 2025. In this case, JEE Advanced will field NTA percentile scores for the minimum marks across different categories as General, OBC-NCL, SC, ST and Gen-EWS.

Candidates aspiring to appear for JEE Advanced in 2025 can have an estimate of the expected cutoff by referring to the cutoff marks of previous years and analyze the qualifying percentile.
Understanding Qualification for JEE Advanced
It is simply a screening test for JEE Advanced, which leads to IITs, stated IIMC. Therefore, the cutoff scores of JEE Advanced would have been considered based on several parameters, including how many candidates were appearing for the exam, the level of difficulty, and the overall performance. Scores are presented in percentile form as minimum cutoff marks so that the scores are normalized across multiple shifts.
Top IITs and Their Cutoff Ranks
Below is an approximate rank range required to get into various IITs.
IIT | Expected Rank Range for Admission (General Category) |
IIT Bombay | 1 – 2500 |
IIT Delhi | 1 – 3000 |
IIT Madras | 1 – 3500 |
IIT Kanpur | 1 – 4000 |
IIT Kharagpur | 1 – 4500 |
IIT Roorkee | 1 – 5000 |
IIT Hyderabad | 1 – 5500 |
Previous Year Cutoff Trends
To provide a better understanding, below is a comparison of cutoffs from previous years.
Cutoff (Expected) 2024
Category | JEE Main 2024 Percentile |
---|---|
Unreserved (UR) | 93.2362181 – 100.0000000 |
OBC-NCL | 79.6757881 – 93.2312696 |
SC | 60.0923182 – 93.2312696 |
ST | 46.6975840 – 93.2312696 |
UR-PwD | 0.0018700 – 93.2041331 |
Cutoff (2023 )
Category | Cutoff |
---|---|
Common Rank List | 90.7788642 |
Gen-EWS | 75.6229025 |
OBC-NCL | 73.6114227 |
SC | 51.9776027 |
ST | 37.2348772 |
PwD | 0.0013527 |
Cutoff (2022)
Category | Cutoff (Percentile) |
---|---|
Common Rank List (CRL) | 88.4121383 |
GEN-EWS | 63.1114141 |
OBC-NCL | 67.0090297 |
SC | 43.0820954 |
ST | 26.7771328 |
PwD | 0.0031029 |
How is the Cutoff Determined?
The cutoff for JEE Advanced is based on various factors:
- Number of students appearing for JEE Main.
- Difficulty level of the exam.
- Total number of available seats in IITs.
- Normalization of scores across multiple shifts.
Expected JEE Main 2025 Cutoff
The cutoff for JEE Advanced will be declared based on the exam but we can read about the trends and the probable percentile needed by the General, the OBC-NCL categories candidates to appear in JEE Advanced will be about 90-93 percentile and 73-80 percentile respectively.
Expected JEE Main 2025 Cutoff:
Category | Expected Percentile Range |
General (UR) | 91-94 |
OBC-NCL | 75-80 |
SC | 50-55 |
ST | 35-40 |
PwD | 0.001-2.0 |
JEE Main 2025 Important Dates
Below are the key dates for :
Events | January Session | April Session |
---|---|---|
Release of Application Form | 28-Oct-2024 | 31-Jan-2025 |
Last Date to Fill the Form | 22-Nov-2024 | 24-Feb-2025 |
Intimation of Exam City | 10-Jan-2025 | March last week |
Release of Admit Card | 20-Jan-2025 | March last week |
Exam Date | 22-30 Jan 2025 | 1-8 April 2025 |
Display of Answer Key | 6-Feb-2025 (Tentative) | To be notified |
Declaration of Result | 12-Feb-2025 | 15-Apr-2025 |
How to Calculate Rank from Percentile?
Candidates can estimate their rank using the following formula: For example,
Let’s assume:
Your NTA score = | P |
Total Number of Students = | N |
Percentage of students below or equal to your marks = | PFor example: if you have secured a 70 percentile in JEE Main, which means that 70% of the candidates who appeared for JEE Main are below or at the same level as you are |
Percentage of students above your marks = | 100 – P |
Number of students above your marks | ((100 – P)/100)*N |
Now, the formula to calculate JEE Main Rank from Percentile Score is:
((100 – P)/100)*N 1
The rank generated will be the probable All India Rank (AIR) you can expect to secure in JEE Main. The actual rank might differ owing to different factors.
Factors Affecting Cutoff
Number of Available Seats: The number of seats in IITs also impacts the cutoff range.
Number of Candidates Appearing: Higher participation leads to higher cutoffs.
Difficulty Level of the Exam: A tougher exam results in a lower cutoff and vice versa.
Previous Year Cutoff Trends: Cutoffs usually follow a trend with slight variations.
JEE Main Answer key 2025 Session 1
For Answer Key Of JEE Main 2025 Session 1 visit: Govdunia( Answer Key )
FAQs on Cutoff
Q1: What is the minimum percentile required to qualify for JEE Advanced 2025?
A: The minimum percentile required to qualify for JEE Advanced varies each year. Based on previous trends, the expected cutoff for the General category is around 90 percentile, while it may be lower for reserved categories.
Q2: How many candidates qualify for JEE Advanced?
A: The top 2.5 lakh candidates who clear JEE Main will be eligible to appear for JEE Advanced.
Q3: With 85 percentile in JEE Main, can I appear for JEE Advanced?
A: Based on previous years’ cutoffs, an 85 percentile score is below the qualifying threshold for General category candidates. However, candidates in reserved categories may still qualify.
Q4: What is the approximate rank for a candidate scoring 150 marks in JEE Main?
A: The rank corresponding to a 150-mark score depends on factors like paper difficulty and the number of candidates appearing. However, an estimate based on previous years suggests a rank range of 20,000-35,000.
Q5: What is the minimum rank required for IIT Bombay?
A: Admission to IIT Bombay requires a very high rank. For general category students, a rank within the top 2000-2500 is typically required for popular branches like Computer Science and Electrical Engineering.
Conclusion
The JEE Main 2025 cutoff for JEE Advanced qualification will be reliant heavily on multiple factors and to be eligible, efforts of candidates should be towards scoring for a good percentile. It is advised to aspirants to keep an eye on NTA notifications and concentrate on learning basics to score the maximum.
Stay tuned for official announcements, and best of luck with your preparation!
For more information, visit the official website of JEE Main: jeemain.nta.nic.in.
Stay tuned for further updates regarding JEE Main 2025 results and JEE Advanced 2025 details!
JEE Main Session 1 (29 January paper analysis): Click Here
JEE Main Session 1 (28 January Paper analysis): Click Here
JEE Main Session 1 (24 January Paper analysis): Click Here
JEE Main Session 1 (23 January Paper analysis): Click Here
JEE Main Session 1 (22 January Paper analysis): Click Here
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FOR REGESTRATION OF JEE MAIN 2025 SESSION 2 : CLICK HERE
For Answer Key Of JEE Main 2025 Session 1 visit: Govdunia( Answer Key )
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